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Stefan Vaziri
17,453 PointsQuestion for zippy.py
Not sure why I'm not getting the right answer here.
# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
# If you use .append(), you'll want to pass it a tuple of new values.
def combo(iter1, iter2):
my_tuple = []
for index, item in enumerate(iter1):
my_tuple.append((item, iter2[index]))
return my_tuple
1 Answer
Chris Freeman
Treehouse Moderator 68,441 PointsYour return statement is indented too far and causes the loop to end after one iteration.. Unindent the return to fix the issue.
def combo(iter1, iter2):
my_tuple = []
for index, item in enumerate(iter1):
my_tuple.append((item, iter2[index]))
return my_tuple
It helps to use 4-space indents to see alignment more clearly.