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Sujal khatiwada1,525 Points
ELECT MANAGERS.FIRST_NAME, MANAGERS.LAST_NAME FROM MANAGERS JOIN EMPLOYEES ON EMPLOYEES.MANAGER_ID = MANAGERS.ID GROUP BY MANAGERS.ID .........................
Brendan WhitingFront End Web Development Techdegree Graduate 84,702 Points
SELECT MANAGERS.FIRST_NAME, MANAGERS.LAST_NAME FROM MANAGERS JOIN EMPLOYEES ON EMPLOYEES.MANAGER_ID = MANAGERS.ID GROUP BY MANAGERS.ID HAVING COUNT(1) > 5;
"HAVING" is like "WHERE" but to use with aggregate functions. COUNT is the aggregate function. It's a little bit confusing the order of the clauses. We GROUP BY by MANAGERS.ID column from the EMPLOYEES table, so it will count the number of employees that have the same manager and only show the records where the count is greater than 5.