Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialErik Embervine
Python Development Techdegree Student 2,442 PointsQuiz question 1 solution seems redundant?
it looks like 2 copies of the restaurants list was made before looping through them to eliminate the non-taco restaurants...is this necessary? i cut down the code to be this:
all_restaurants = [
"Taco City",
"Burgertown",
"Tacovilla",
"Hotdog station",
"House of tacos",
]
def tacos_only(restaurants):
for restaurant in restaurants.copy():
if "taco" not in restaurant.lower():
restaurants.remove(restaurant)
return restaurants
dinner_options = tacos_only(all_restaurants)
print(dinner_options)
...and it seems to do the same thing. is the taco_joints reassignment and taco_joints.copy necessary?
1 Answer
Steven Parker
231,275 PointsThe creation of taco_joints allows the function to return a modified list without changing the original list.
With the modifications shown above, the function will alter the original list of all_restaurants.
Erik Embervine
Python Development Techdegree Student 2,442 PointsErik Embervine
Python Development Techdegree Student 2,442 Pointsok I see. thanks!