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Python Introducing Lists Using Lists Review Mutability

Posted by Erik Embervine
.a{fill-rule:evenodd;}techdegree
Erik Embervine
Python Development Techdegree Student 2,442 Points

Quiz question 1 solution seems redundant?

it looks like 2 copies of the restaurants list was made before looping through them to eliminate the non-taco restaurants...is this necessary? i cut down the code to be this:

all_restaurants = [
    "Taco City",
    "Burgertown",
    "Tacovilla",
    "Hotdog station",
    "House of tacos",
]

def tacos_only(restaurants):
    for restaurant in restaurants.copy():
        if "taco" not in restaurant.lower():
            restaurants.remove(restaurant)
    return restaurants

dinner_options = tacos_only(all_restaurants)
print(dinner_options)

...and it seems to do the same thing. is the taco_joints reassignment and taco_joints.copy necessary?

1 Answer

Steven Parker
Steven Parker
231,268 Points
Steven Parker
Steven Parker
231,268 Points

The creation of taco_joints allows the function to return a modified list without changing the original list.

With the modifications shown above, the function will alter the original list of all_restaurants.

Erik Embervine
.a{fill-rule:evenodd;}techdegree
Erik Embervine
Python Development Techdegree Student 2,442 Points

ok I see. thanks!