Quiz question

You are offsetting your $i at the start of the loop, so you are missing the first index of the array

 $i = $i + 1;

What happens here is that the first time the loop runs, it is making $i set to 1 instead of zero. Since the length of the array is 4, when the loop goes through the last index, it sees that $i = 4, so your if condition is now false. If you move that after your if block, it should now be 4321.

$numbers = array(1,2,3,4);

$total = count($numbers);

$sum = 0;

$output = "";

$i = 0;

foreach($numbers as $number) {



    if ($i < $total) {

        $output = $number . $output;

    }

  $i = $i + 1;

}

echo $output;

Is your intention to make the numbers go in order?

$output = $number . $output;

The above code there is appending the $number to the beginning of $output. Reversing those two will make the numbers go in traditional order. Another suggestion is that depending on what it is you are trying to do, you can just echo out $number inside of your if block instead of concating the string and doing it at the end of the loop. Like this:

foreach($numbers as $number) {

    if ($i < $total) {

        echo $number;

    }

  $i = $i + 1;

}

Finally you can take $i = $i + 1; and turn it into `$i++', which does the same thing. Let me know if this helps or you still find yourself confused.