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john paul
3,191 Pointsquiz question
Hi, in this quiz question, the following code did not display anything in the workspace.
$username = "Treehouse"; if ($username) { if ($username != "Treehouse") { echo "Hello $username"; } }else { echo "you must be logged in"; }
I answered the question correctly (as ''would not display anything'') but only because I tested my own answer first by writing the code into my work space. I have to admit that I do not fully understand why though, as I first of all expected the answer ''you must be logged in". I am confused as to what the first if statement is attempting to do as their are no conditionals , just if($username). I suspect this must be the reason why nothing is displayed, but am not sure why. Can anyone explain why this code displays nothing. Thank you.
Steven Snary
17,540 PointsI'm glad the answer provided was beneficial - if you feel my answer was adequate please mark it as the accepted or best answer.
Thanks
1 Answer
Steven Snary
17,540 PointsThe outer IF..ELSE equates to true so the code executes the TRUE branch of the outer IF statement (This means that "You must be logged in will never run)
The inner IF..ELSE equates to FALSE so the "Hello $username" will not run
Since there is no ELSE on the inner IF then nothing is displayed and the code exits
john paul
3,191 Pointsjohn paul
3,191 Pointsahhhh!! makes perfect sense, thank you.