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Calvin Secrest24,812 Points
Recursive binary search with iterative
So if we continue with this code snippet and tried to verify the call would it look like this:
def recursive_binary_search(list, target, start=0, end=None): if end is None: end = len(list) - 1 if start > end: return -1 mid = (start + end) // 2 if target == list[mid]: return mid else: if target < list[mid]: return recursive_binary_search(list, target, start, mid-1) else: return recursive_binary_search(list, target, mid+1, end) # The if statement returns the index position of the target if found, else returns None def verify(result, index): print("Target found: ", result) elif index is not None: print("Target found at index: ", index) elif: print("Target not found in list") numbers = [1,2,3,4,5,6,7,8] result = recursive_binary_search(numbers, 12) verify(result) result = result = recursive_binary_search(numbers, 6) verify(result)