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14,136 PointsRegex dictionary
I've spent an age on this and still can't get it. The individual parts in the below, pickup last name or first name and the age. and work with players.groupdict(). However combining them seems to great a list eg. with:
players = re.findall(r'(?P<last_name>[\w]+), (?P<first_name>[\w]+)', string, re.M)
No idea why that doesn't work as a dictionary?
Also I'm not sure how to pick up multiple last names or first names.
eg. '(?P<last_name[\w]+ [\w]+?), ......
import re
string = '''Love, Kenneth: 20
Chalkley, Andrew: 25
McFarland, Dave: 10
Kesten, Joy: 22
Stewart Pinchback, Pinckney Benton: 18'''
players = re.search(r'(?P<last_name>[\w]+), (?P<first_name>[\w]+): (?P<score>[\d]+)', string, re.M)
5 Answers
Simon Leslie
23,690 PointsI can answer the second part of your query (about multiple last names / first names): you should include an explicit space in the set being search for like this:
(?P<last_name>[\w ]+)
There is space just after the '\w'.
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14,136 PointsThanks that helps, not sure why that works is [\w ]+ a set with 1 or more letter or spaces?
Now I have:
players = re.findall(r'(?P<last_name>[\w ]+), (?P<first_name>[\w ]+): (?P<score>[\d]+)', string, re.M)
Which produces a list: [('Love', 'Kenneth', '20'), ('Chalkley', 'Andrew', '25'), ('McFarland', 'Dave', '10'), ('Kesten', 'Joy', '22'), ('Stewart Pinchback', 'Pinckney Benton', '18')]
not sure why?
Simon Leslie
23,690 Points[\w ]+ will match a sequence of one or more characters (\w) or spaces.
As for the result being list, you are using .findall() instead of .search() or .match().
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14,136 PointsThanks that was it. I forgot to change it back after testing.
Kenneth Love
Treehouse Guest Teacher[\w\s] should work, too, for the names. You were, originally, just catching [\w] which won't match the spaces.