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Python Write Better Python Buggy Logs The Python Debugger

Script Code
Script Code
6,631 Points
Posted by Script Code
Script Code
6,631 Points

remove method removes 1 instead of True from list

If you have a list with a Boolean value True at index 0 and int 1 at index 1. How do you remove True using the remove method?

my_list = [1, True] my_list.remove(True) This returns [True]

I am aware that 1 == True returns True and that; 1 is True returns False False

Because 1 and True are not the same objects id(1) returns 1697929488 whilst, id(True) returns 1697748080

However I am not able to think of a way to perform the above. HELP!! :)

3 Answers

Alexander Davison
Alexander Davison
65,469 Points
Alexander Davison
Alexander Davison
65,469 Points

If you want to delete an item in a list, there's two ways.

One is by index, the other way is to do it by element. Here's some examples:

# Here's a list of the alphabet
my_list = list('abcdefghijklmnopqrstuvwxyz')

# This is the index way of deleting items
del my_list[0] # This will delete "a" because "a" is at index 0.

# This is the element way of deleting items
my_list.remove('z') # This will remove "z" from the list.

so, to solve your problem, you could do this:

your_list = [True, 1]

# This will delete True
your_list.remove(True)

Hope it helps! :) ~Alex

Script Code
Script Code
6,631 Points
Script Code
Script Code
6,631 Points

Hi Alex,

But what if the list order is [1, True]? Does this mean I have to reorder the list before I can use the remove method?

Alexander Davison
Alexander Davison
65,469 Points

Big no no! This code will still work because I'm telling Python to search for True in your list and if there is one, Python will delete it.

Script Code
Script Code
6,631 Points
Script Code
Script Code
6,631 Points
  1. your_list = [True, 1]
  2. your_list.remove(True) # This returns [1]

However (1 and True in different order):

  1. my_list = [1, True]
  2. my_list.remove(True) # This returns [True]
Alexander Davison
Alexander Davison
65,469 Points

Hmm... That's strange. Try deleting by indexes like this then:

your_list = [True, 1]
del your_list[0]
boi
boi
14,241 Points
boi
boi
14,241 Points

For Future audience.

The reason you are getting True in return is because True == 1

There are two scenarios here, the first case scenario

your_list = [True, 1]

your_list.remove(True)  #Returns [1]

The second case scenario

my_list = [1, True]

my_list.remove(True) # Returns [True]

1 is considered True and 0 is considered False, Also note that the remove function, if used on a list having duplicate objects, will remove the first duplicate or will remove them in order, The above case scenarios proofs this behavior.

Try these exercises

my_list = [1, True]

print(sum(my_list))  #The function "sum" returns the summation of the objects in the list

my_list = [False,True]

print(sum(my_list))  #The function "sum" returns the summation of the objects in the list