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Python

Posted by Tatenda Marshall Manuel
Tatenda Marshall Manuel
8,055 Points

removing items from a list

i need you to finish writing a function for me.The function disemvowel takes a single word as a parameter and then returns that word at the end. I need you to make it so, inside of the function, all of the vowels ("a", "e", "i", "o", "u")

Tatenda Marshall Manuel
Tatenda Marshall Manuel
8,055 Points

def disemvowel(word): vowels = ["a", "e", "i", "o", "u"] vowels = [ element.lower() for element in vowels] new_list [] for letter in list(word): if not letter.lower()in vowels new_list += letter new_list =".join(new_list) return new_list

1 Answer

Oszkár Fehér
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.a{fill-rule:evenodd;}techdegree seal-36
Oszkár Fehér
Treehouse Project Reviewer
Oszkár Fehér
.a{fill-rule:evenodd;}techdegree seal-36
Oszkár Fehér
Treehouse Project Reviewer

Hi Marshall. You are very close This lines are ok

def disemvowel(word): 
    vowels = ["a", "e", "i", "o", "u"]

you can also define vowels like so:

    vowels = 'aeiou'

This is a list to. The third line you don't need

vowels = [ element.lower() for element in vowels]

After this when you define the "new_list", it's missing the "=" sign

new_list = []

In the for loop you don't need to convert to a list the incoming "word" variable

for letter in word:

Remember, string it's already a list. These 2 lines are ok to just it's missing the ":" from the "if" statement and a space before the "in" keyword

if not letter.lower() in vowels:
    new_list += letter

From here you can return the result directly

return "".join(new_list)

So overall it looks like this:

def disemvowel(word):
    vowels = ["a", "e", "i", "o", "u"]
    new_list = []
    for letter in word:
        if not letter.lower() in vowels:
            new_list += letter
    return ''.join(new_list)

Or a very short version 

def disemvowel(word):
    vowels = ["a", "e", "i", "o", "u"]
    return ''.join(letter for letter in word if letter.lower() not in vowels)

I hope it will help you to figure out. Happy coding