Removing more than 1 element using pop and shift method?

You could mimic the behavior of .pop() or .shift() for multiple elements using .splice() (not to be confused with .slice()):

arrayName.splice(startIndex, deleteHowMany)

To return elements deleted from the beginning, use a start index of 0:

var arr = ['a', 'b', 'c', 'd'];
var first2 = arr.splice(0, 2); // first2 is [ "a", "b" ] 
// arr is now [ "c", "d" ]

To return elements deleted from the end, use a negative index (-1 for last, -2 for next-to-last, etc):

Array [ "a", "b", "c", "d" ]
var last2 = arr.splice(-2, 2); // last2 is [ "c", "d" ] 
// arr is now [ "a", "b" ]

here is a link to the MDN doc page for splice.

You could use a loop to remove multiple items from an array using pop and shift, but each call may only remove a single element.

If you'd like to remove multiple elements perhaps splice might work better for you?

You can create a function for this purpose. Like I did here :

var numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9];

function removeItems(arr, item) {
    for ( var i = 0; i < item; i++ ) {
        arr.pop();
    }
}

removeItems(numbers, 2);