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Python Python Collections (2016, retired 2019) Lists Disemvowel

Joshua Bowden
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Joshua Bowden
Full Stack JavaScript Techdegree Graduate 29,312 Points

Removing the vowels from a word function:

My code should be removing all of the letters that don't fit but for some reason is failing specifically on the u's which is weird.

def disemvowel(word):
    letters = []
    for letter in letters:
        if letter == 'a' or letter == 'A' or letter == 'e' or letter == 'E' or letter == 'i' or letter == 'I' or letter == 'o' or letter == 'O' or letter == 'u' or letter == 'U':
    word = "".join(letters)
    return word

1 Answer

Jennifer Nordell
Jennifer Nordell
Treehouse Teacher

Hi there, Joshua Bowden ! The problem here is that you're changing the thing you're iterating over which is essentially messing up the indexing. What this means is that whenever you remove a letter, the check on the next letter will be skipped. That's not a problem when the next letter is a consonant, but it is a problem when the next letter is a vowel.

The way to mitigate this would be to first create a copy of that list. You can either iterate over the original list and change the copy, or iterate over the copy and change the original, but the one you're iterating over should not be changed. Then at the end, take the changed version and rejoin it to be a string and return it.

Hope this helps! :sparkles: