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JavaScript Introduction to Programming Objects and Arrays Arrays

Jeremy Dortch
Jeremy Dortch
3,799 Points
Posted by Jeremy Dortch
Jeremy Dortch
3,799 Points

Repeating the 0 place in the array

var friends = ["Jake", "Jordan", "Will", "Jordi", "Jon"];
console.log(friends);
console.log(friends.length);

var friendNumber = 1;
console.log(friends[friendNumber]);

for(var i=0; i < friends.length; i+=1){
console.log(friends[i]);
}

For some reason it's spitting out the following:

Jordan Jake Jordan Will Jordi Jon

I don't know why it's replacing Jake with Jordan and repeating it before and after.

Thanks!!!

2 Answers

Andrew Shook
Andrew Shook
31,709 Points
Andrew Shook
Andrew Shook
31,709 Points

Jeremy Dortch, the output is correct. The first Jordan is being printed because this line:

var friendNumber = 1; 
console.log(friends[friendNumber]);

//actually printing
console.log(friends[1]);

Remember, arrays are zero indexed, meaning that they start counting at zero and not one. 

array[

0 => "Jake",
1 => "Jordan",
2 => "Will",
3 => "Jordi"
4 => "Jon".
]

So when you tell JavaScript to get position 1 you are really telling it to get the second item in the array.

Now in the for loop, you are telling JS to start at position 0:

for(var i=0; i < friends.length; i+=1)

Position zero is Jake. So first you tell it to print position 1, Jordan, then you tell it to print the whole array starting at position 0 and going through position 4 ( Jake, Jordan, Will, Jordi, Jon). So that's why is prints :

`` Jordan Jake Jordan Will Jordi Jon

Jack Choi
Jack Choi
11,420 Points
Jack Choi
Jack Choi
11,420 Points

I think the output looks correct. The first "Jordan" is being printed by the console log here and maybe that's what's throwing it off:

var friendNumber = 1; console.log(friends[friendNumber]);

newline is your friend!