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PHP PHP Arrays and Control Structures PHP Arrays Multidimensional Arrays

Ramona marian
Ramona marian
1,126 Points

Replace the hard coded values in the output with the name and email values from the contacts array.

My code doesn;t work

//edit this array
$contacts = array('Alena Holligan', 'Dave McFarland', 'Treasure Porth', 'Andrew Chalkley');
$contacts = [
  ["name" => "Alena Holligan",
   "email" => "alena.holligan@teamtreehouse.com"], 
  ["name" => "Dave McFarland",
   "email" => "dave.mcfarland@teamtreehouse.com"], 
  ["name" => "Treasure Porth",
   "email" => "treasure.porth@teamtreehouse.com"], 
  ["name" => "Andrew Chalkley",
   "email" => "andrew.chalkley@teamtreehouse.com"]

echo "<ul>\n";
//$contacts[0] will return 'Alena Holligan' in our simple array of names.
echo "<li> Alena Holligan : alena.holligan@teamtreehouse.com</li>\n";
echo "<li>Dave McFarland : dave.mcfarland@teamtreehouse.com</li>\n";
echo "<li>Treasure Porth : treasure.porth@teamtreehouse.com</li>\n";
echo "<li>Andrew Chalkley : andrew.chalkley@teamtreehouse.com</li>\n";
echo "</ul>\n";

echo "<ul>\";

echo "<li>" . $contacts[0]["name"] . " : " . $contacts[0]["email"] . "</li>\n";
echo "<li>" . $contacts[1]["name"] . " : " . $contacts[0]["email"] . "</li>\n";
echo "<li>" . $contacts[2]["name"] . " : " . $contacts[0]["email"] . "</li>\n";
echo "<li>" . $contacts[3]["name"] . " : " . $contacts[0]["email"] . "</li>\n";

1 Answer

Steven Parker
Steven Parker
228,013 Points

The challenge wants you to "Replace the hard coded values in the output..." (not echo them a second time).

Also, the index values for the email must match the ones for the name on each line (instead of all being 0).