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JavaScript Introduction to jQuery DOM Traversal Why We Traverse the DOM

parker keller
parker keller
6,539 Points
Posted by parker keller
parker keller
6,539 Points

reset form code not working

having trouble with the reset form field not resetting, despite only changing the names to what Aisha specifies ($name, $species, $notes). One thing I am confused on is that in some videos we have things like

var $name = $('#pet-name').val(); var $species = $('#pet-species').val(); var $notes = $('#pet-notes').val();

where val() is included, yet in this video it is gone?? When I try to delete it from my code and use the post a pet form, it just gives me output of [object object], so how is it still working for her despite not having it? Not sure if that is changing the functionality of the form or not, but it definitely is confusing the heck out of me and she does not mention it at all

parker keller
parker keller
6,539 Points
parker keller
parker keller
6,539 Points

i should also note that everything else functions fine, just not the form reset functionality (which worked prior to making the code more DRY). also the chrome console provides an error for the update reset form code that states "Uncaught TypeError: $name.val is not a function"

1 Answer

ymusthof
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.a{fill-rule:evenodd;}techdegree
ymusthof
Front End Web Development Techdegree Student 12,035 Points
ymusthof
.a{fill-rule:evenodd;}techdegree
ymusthof
Front End Web Development Techdegree Student 12,035 Points

Hi, Have you thought to add .val() for each var inside $newPet? 

  var $name = $('#pet-name');
  var $species = $('#pet-species');
  var $notes = $('#pet-notes');

  var $newPet = $(
    '<section class="six columns"><div class="card"><p><strong>Name:</strong> ' + $name.val() +
    '</p><p><strong>Species:</strong> ' + $species.val() +
    '</p><p><strong>Notes:</strong> ' + $notes.val() +
    '</p><span class="close">&times;</span></div></section>'
  );

  $name.val("");
  $species.val("Dog");
  $notes.val("");

I think if you don't add .val() for each var inside $newPet, it will return object only without any value.

Thaddeus Papciak
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.a{fill-rule:evenodd;}techdegree
Thaddeus Papciak
Front End Web Development Techdegree Student 6,722 Points
Thaddeus Papciak
.a{fill-rule:evenodd;}techdegree
Thaddeus Papciak
Front End Web Development Techdegree Student 6,722 Points

Yeah that works, would have been helpful for this to be pointed out in video. Im starting to feel like this course needs to be updated. I keep running into stuff like this. Im going back and reviewing the videos looking for something I thought I missed. At least its not just me.