Didier Borel2,837 Points
return an iterable
I don't understand why I am getting an error here
# EXAMPLE # random_item("Treehouse") # The randomly selected number is 4. # The return value would be "h" import random define random_item ("iterable"): random_number=random.randint (len("iterable")-1) return "iterable"(random_number)
There are quite a few issues in your code:
- Functions in Python are defined using the
- Parameters (the thing that goes within parenthesis of function declarations) cannot be literal values like strings or a number. Parameters are essentially variables that are passed a value when the method is called. So the parameter has to be a name that you will use to reference that value inside of your code.
randintmethod takes two arguments, the lowest possible number to generate, and the highest. You have only provided it with the highest number to generate.
- When pulling out an index from an iterable source you have to use square brackets  not parenthesis ().
If you fix all of those issues like this:
import random def random_item(itr): # Parameter is named itr and def is used instead of define random_number = random.randint(0, len(itr)-1) # Provide minimum number to generate return itr[random_number] # Use square brackets when pulling index out of parameter
Then your code will pass.