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# Return larger number...

Hi... so, first I thought I didn't get the question, because it is quite confusing to me. But after trying out several solutions I just got stuck on the conditional. This is my code right now, but it always claims a syntax error... any ideas?

script.js
```function max(3,8) {
if (parseInt(3) < parseInt(8)) {
return 8;
}
}
```

those numbers are already integers... no need to parse them.

if you want to create something that works programmatically you are better off like this

function max (x, y) { if (x < y) { return y; } else { return x; } }

and then calling the function like this

max(3, 8);

so when you call the function you are telling it to compare whatever you call as the arguments rather than it just comparing something you already have numbers for :) i know thats a bit of a jump from what you are looking at, but i hope helps

hiya Daniela! In real world issues, i like your approach. But you're doing way too much stuff in context of the challenge. Your function recieves two arguments and your function does a conditional to check which number is greater than the other and return it. All ya have to is return the greater number using "if else" statement. Here is my code

```function max(x, y) {
if(x > y) {
return x;
} else {
return y;
}
}
```

hahah, how about that for posting the exact same thing moments apart!

Hiya blake guyan ! Haha yeah! I dont care as long as Daniela Kersting and other students gets it. (:

Thank you both so much! I kept on trying and I finished the challenge like 20 minutes after asking the question. But with your answers I get it even more.

Thank you!!!