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Ruby Ruby Operators and Control Structures Logical Operators The And (&&) Operator

Posted by Zachary Dunn
Zachary Dunn
6,557 Points

return was not covered in the previous video tutorial. how do i set the return value to equal a string?

how to set the return value

ruby.rb 
def check_speed(car_speed)
  # write your code here
  if (car_speed > 40) && (car_speed <= 50)
    return 'safe'
end

1 Answer

Cauli Tomaz
Cauli Tomaz
12,362 Points
Cauli Tomaz
Cauli Tomaz
12,362 Points

Ruby doesn't require the "return" statement. It will always return the last variable of the function.

You can use it to force-exit from a function early though (http://stackoverflow.com/questions/4601498/what-is-the-point-of-return-in-ruby)

def check_speed(car_speed)
  warning = 'unsafe'
  if (car_speed > 40) && (car_speed <= 50)
    warning = 'safe'
  end
  warning
end

or 

def check_speed(car_speed)
  if (car_speed > 40) && (car_speed <= 50)
    'safe'
  else
    'unsafe'
  end
end
Cauli Tomaz
Cauli Tomaz
12,362 Points
Cauli Tomaz
Cauli Tomaz
12,362 Points

Edit: I forgot to add an 'end' to the if statement. This is also your case, and this might be causing your problem.

Zachary Dunn
Zachary Dunn
6,557 Points

its still not working... hmmm

Cauli Tomaz
Cauli Tomaz
12,362 Points
Cauli Tomaz
Cauli Tomaz
12,362 Points

The problem is logic, not the ruby syntax.

I've read the problem and it states "The speed must be at least 40" and you are using (car_speed > 40)

This makes a speed of at least "41"!

Zachary Dunn
Zachary Dunn
6,557 Points

nope. still not working

Cauli Tomaz
Cauli Tomaz
12,362 Points
Cauli Tomaz
Cauli Tomaz
12,362 Points

Correct answer, tested:

def check_speed(car_speed)
  if (car_speed >= 40) && (car_speed <= 50)
    'safe'
  end
end
Zachary Dunn
Zachary Dunn
6,557 Points

Thank You, Thank you...