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# Returning True or False instead of the list

Letβs say I give you a list saved in a variable: a = [1, 4, 9, 16, 25, 36, 49, 64, 81, 100]. Write one line of Python that takes this list a and makes a new list that has only the even elements of this list in it.

a = [1, 4, 9, 16, 25, 36, 49, 64, 81, 100] b = [num % 2 == 0 for num in a]

print(b)

why does this only return "True" or "False" but not the numbers themselves?

You want to create b like this:

```b = [num for num in a if num % 2 == 0]
```

This way it will iterate over the numbers in a and only add them to b if num % 2 == 0

Thank you. Can you elaborate the difference between this line and mine though?

The way you have it, it's iterating over a and just checking if each num % 2 == 0, and returning the boolean value. Think of its this way...

```for num in a:
return num % 2 == 0
```

where you can think of the way i wrote it as:

```for num in a:
if num % 2 == 0:
b.append(num)
return b
```