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Andrew Walters
8,876 PointsRuby Loop, Challenge One
Hey guys! So I'm really struggling on the first Loop Challenge in Ruby which is asking us to insert a variable into an array, and then to count that variable up (via a loop) and when you reach 3 the loop should end. I could swear that I am doing it right but I don't seem to be passing the challenge. I would either get a void value message or "You're code took too long to run". Can anyone help to explain what I'm doing wrong? Thanks!
numbers = []
number = 0
# write your loop here
loop do
numbers = [number]
number ++
if numbers.length > 3
break
end
end
2 Answers
Kelsey Jackson
UX Design Techdegree Student 63,504 PointsHey Andrew,
You are almost there, you just have some slight syntax errors, the code below should pass:
numbers = []
number = 0
loop do
numbers.push(number)
if numbers.length >= 3
break
else
number += 1
end
end
Kelsey Jackson
UX Design Techdegree Student 63,504 PointsThat break will execute only when the conditional is true, if not it will increment and run again. The wording in the question is a little misleading but >= 3 or >2 would work.
Andrew Walters
8,876 PointsAh, okay I see. Thanks for clarifying it! Much appreciated!
Philip Bessa
5,396 Pointshas more than 3 items should instead state has 3 items or more. It's not misleading, it's just wrong:
if numbers.length > 3
But after it fails, the Bummer message points to a hint (finally it helps for once):
if numbers.length >= 3
Andrew Walters
8,876 PointsAndrew Walters
8,876 PointsThat makes sense but why would you want to break the loop before adding one? And why greater than or equal to 3? The question seems to request a break if above 3 but doesn't indicate if being equal to 3 is okay