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Python Python Basics (2015) Shopping List App Continue

Posted by Alex Crump-Haill
Alex Crump-Haill
7,819 Points

Same issue with similar problem to before!

Apparently cannot convert a str into int implicitly - which I knew - but not sure why it would be the case here!

breaks.py 
def loopy(items):
    # Code goes here
    for item in items:
        if item.index(0) == "a":
            continue
        print(item)

2 Answers

Steven Parker
Steven Parker
229,732 Points
Steven Parker
Steven Parker
229,732 Points

The .index function searches a list for an item. The item should be the same type as the elements of the list.

But that's not what you want here anyway, you already know the index. You want to get the item at index 0.

:point_right: That's done by subscripting, using the index in brackets (like: "item[0]").

Petko Delchev
Petko Delchev
7,414 Points
Petko Delchev
Petko Delchev
7,414 Points

Hi all,

look I did the subscripting, but still bummer...

def loopy(items): # Code goes here for item in items: if item [0] == "a": continue else print(item)