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CSS Sass Basics (retired) Advanced Sass Concepts Advanced Mixin Arguments

Aaron HARPT
Aaron HARPT
19,845 Points
Posted by Aaron HARPT
Aaron HARPT
19,845 Points

sass basics question

I cannot get the answer on this code challenge:

Design a mixin (called "rainbow") that can take any number of colors via the argument $colors.... Within the mixin, use the loop @each $color in $colors to create a class named after each color, and set its background to the corresponding color.

index.html 
<!DOCTYPE html>
<html>
<head>
  <title>Sass Basics - Code Challenge</title>
  <link rel="stylesheet" type="text/css" href="page-style.css">
  <link rel="stylesheet" type="text/css" href="style.css">
</head>
<body>
  <div class="box"></div>
  <div class="red"></div>
  <div class="orange"></div>
  <div class="yellow"></div>
  <div class="green"></div>
</body>
</html>
style.scss 
/* Write your SCSS code below. */
@mixin square($size, $color: black) {
  width: $size;
  height: $size;
  border: 1px solid $color;
}

.box {
  @include square($color: red, $size: 10px);
}

@mixin rainbow($colors...)
{
@each $color in $colors {
  .#{$color} {
    background-color: #{$color};
  }
}
Jesus Mendoza
Jesus Mendoza
23,288 Points
Jesus Mendoza
Jesus Mendoza
23,288 Points

The background-color should be the variable name $color

1 Answer

Krzysztof Kucharzyk
seal-mask
.a{fill-rule:evenodd;}techdegree
Krzysztof Kucharzyk
Front End Web Development Techdegree Student 4,005 Points
Krzysztof Kucharzyk
.a{fill-rule:evenodd;}techdegree
Krzysztof Kucharzyk
Front End Web Development Techdegree Student 4,005 Points

As it's said you have to assign $color variable to the background, not to background-color. This code below suppose to work just fine 

@mixin rainbow($colors...) {
    @each $color in $colors {
        .#{$color} {
            background: $color;
        }
    }
}