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Tim Ruby
Tim Ruby
Courses Plus Student 19,038 Points

Sass Final Exercise 6 of 6

I cannot find an answer, and I am not sure if I am overlooking something, or just making a stupid mistake. I am kinda to the point of giving up on it for a bit. Any feedback would be great.

@mixin rainbow($colors...) {
  @each $color in $colors {
    .#{$color} {
      background: $colors;

@include rainbow(red, orange, yellow, green);

2 Answers

Tom Bedford
Tom Bedford
15,645 Points

Check this thread.

I don't think your background is meant to be red, orange, yellow, and green at the same time.

hint: $colors outputs every color not just one.

Mårten Björk
Mårten Björk
3,776 Points

Like Tom says, in background: $colors; you're referring to all the colors at the same time. Instead you want to use the $color (singular) variable, like background: $color;. The $color variable changes for each iteration of the loop, which means that it will print different colors each time – that's the result you're looking for.