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CSS

SASS interpolation question

So in this example:

@for $i from 1 through 3{
.item_#{$i}{
width: $i * 100px;
}
}

Why is it that in the width: $i * 100px; it is just $i and not #{$i}

also the other way around why can't we just use .item_$i instead of .item_#{$i}

1 Answer

Sass variables can only store values. For dynamic selectors like in this case, you need to use interpolation syntax, otherwise it will output an error.

For instance:

$selector: item;
$value: red;

// Right:
.#{$selector} {
  background: $value;
}

// Wrong:
.$selector {
  background: $value;
}

So interpolation is specifically for selectors rite.. other than that you can use an argument with out interpolation to calculate values like the width correct?

You could also store a property into a variable, than use it with interpolation. For instance:

$bg: background;

.item {
  #{$bg}: red;
}

But yes, you are right, interpolation is used for selectors most of the time, and regular variables are used for values.

I see thanks Matt appreciate it!