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Python

Tiana Manzano
PLUS
Tiana Manzano
Courses Plus Student 2,248 Points
Posted by Tiana Manzano
Tiana Manzano
Courses Plus Student 2,248 Points

score_yatzy

I'm not 100% sure how to make it check that each dice have the same value. I've been trying to search outside sources, hence the "all" but I don't seem to be getting closer to a solution.

scoresheets.py 
class YatzyScoresheet:
    def score_ones(self, hand):
        return sum(hand.ones)

    def _score_set(self, hand, set_size):
        scores = [0]
        for worth, count in hand._sets.items():
            if count == set_size:
                scores.append(worth*set_size)
        return max(scores)

    def score_one_pair(self, hand):
        return self._score_set(hand, 2)

    def score_chance(self, hand):
        return sum(hand)

    def score_yatzy(self, hand, set_size=5):
        if all in self.hand == hand[0]:
            return 50 
        else:
            return 0

1 Answer

Steven Parker
Steven Parker
229,708 Points
Steven Parker
Steven Parker
229,708 Points

There's no "all" defined here, but if you wanted to check each item of a list you might do it with a loop. And remember that "hand" is passed as an argument (so no "self." prefix needed).

Also, the instructions don't ask for a "set_size" argument.

Tiana Manzano
Tiana Manzano
Courses Plus Student 2,248 Points
Tiana Manzano
Tiana Manzano
Courses Plus Student 2,248 Points

I guess what I'm confused about is how I can instruct it to check if all of them are the same, like I understand that it'll check for each item in sequence but I'm confused about how I would go about saying:

for x in hand: if (all items) == (same thing): return 50

See what I mean? I don't know it would compare each item in a list to be similar which is why i tried to use "all"

Thank you so much for your help and patience!

Steven Parker
Steven Parker
229,708 Points
Steven Parker
Steven Parker
229,708 Points

The loop is a good idea, and then you might compare each item to the next one and return 0 if any do not match. Only if they are all the same would you return 50:

        for x in range(len(hand)-1):
            if not hand[x] == hand[x+1]:
                return 0;
        return 50;