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Java

Nancy Melucci
PLUS
Nancy Melucci
Courses Plus Student 36,659 Points
Posted by Nancy Melucci
Nancy Melucci
Courses Plus Student 36,659 Points

Searching text file for target name, trying to avoid an infinite loop and print out integers.

I am working on an assignment where the user inputs a target name and Java searches a text file for the line that starts with that name and then prints out the rankings for a century of name popularity.

What I have posted here is an intermediate step, so I haven't dealt with the Scanner for user input. I am just trying to search the file for the name and print out the integers, and then skip the rest of the file.

I am still too new at this to figure out how to do that without triggering an infinite loop.

I am posting my code and a small portion of the text file. I am going to replace the awkward, non-DRY integer variables with a for-loop. But I need to fry this fish first.

Thanks for any guidance you can give me. I have been doing well in this course. This will be my first late assignment if I can't figure out how not to be such an idiot about while loops soon...><

/**
 *
 * @author Nancy
 */
import java.io.*;//file processing
import java.util.*;
//import java.util.Scanner;

public class FileInfo {

    public static void main(String[] args)
        throws FileNotFoundException, IOException {
            Scanner baby = new Scanner(new File("babynames.txt"));
            int decadeOne = 0, decadeTwo = 0;

           String target = "Aaron";

          while (baby.hasNext()){
            if (!baby.hasNext(target)){
                 baby.next();
            }
                 else if (baby.hasNextInt()){
      // the String to int conversion happens here
            decadeOne = baby.nextInt();
            decadeTwo = baby.nextInt();
            int decadeThree = baby.nextInt();
            int decadeFour = baby.nextInt();
            int decadeFive = baby.nextInt();
            int decadeSix = baby.nextInt();
            int decadeSeven = baby.nextInt();
            int decadeEight = baby.nextInt();
            int decadeNine = baby.nextInt();
            int decadeTen = baby.nextInt();
            int decadeEleven = baby.nextInt();





            } if (baby.hasNext("\n")) 
                break;
              System.out.println(decadeOne);
                System.out.println(decadeTwo); 

          } System.out.println("End outer loop");

}
}

A 83 140 228 286 426 612 486 577 836 0 0
Aaliyah 0 0 0 0 0 0 0 0 0 380 215
Aaron 193 208 218 274 279 232 132 36 32 31 41
Abagail 0 0 0 0 0 0 0 0 0 0 958
Abbey 0 0 0 0 0 0 0 0 537 451 428
Abbie 431 552 742 924 0 0 0 0 752 644 601
Abbigail 0 0 0 0 0 0 0 0 0 953 562
Abby 0 0 0 0 0 906 782 548 233 211 209
Abdiel 0 0 0 0 0 0 0 0 0 925 721
Jeremy Hill
Jeremy Hill
29,567 Points

I would add another String declaration in there to put each word in that the Scanner reads. Like:

String line = "";
line = baby.next();
if(line.startsWith(target)){
  //run this code
}
else{
  //run this code instead
}

3 Answers

Simon Coates
Simon Coates
28,695 Points

Might try something like:

import java.io.*;//file processing
import java.util.*;
//import java.util.Scanner;

public class Reader {

    public static void main(String[] args)
            throws FileNotFoundException, IOException 
    {
          Scanner baby = new Scanner(new File("babynames.txt"));

          String target = "Aaron";

         while (baby.hasNextLine()){
             String ln = baby.nextLine();
             System.out.println(ln);
             String[] lineSegs = ln.split(" ");
             if(lineSegs[0].equals(target))  {
                 System.out.println("Found");
                 //use indices to get ints.

                 break;
             }
         }
   }
}

I think you're supposed to close a scanner at the end.

Jeremy Hill
Jeremy Hill
29,567 Points

You're welcome :)