Second shopping list

Question

My loopy function needs to skip an item.
Loop through each item in items. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member.
Example: ["abc", "xyz"] will just print "xyz".
My solution:
def loopy(items):
    items = ["abc", "xyz"]
    for item in items:
        if item[0] == "a":
            continue
        print(item)
        else:
            break
            print(item)
```breaks.py
def loopy(items):
        items = ["abc", "xyz"]
    for item in items:
        if item[0] == "abc":
            continue
        print(item)
```

Henrik Christensen · Accepted Answer

You are very close.
you should not create a variable named items - items would be the argument.
also, you would want to check if item[0] == 'a' instead of checking item[0] == 'abc'
```python
def loopy(items):
    # loop through items
    for item in items:
        # if character at [0] == 'a'
        if item[0] == 'a':
            # then continue
            continue
        # else print item
        print(item)

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Shamushideen Sule

Shamushideen Sule

Second shopping list

1 Answer

Henrik Christensen

Henrik Christensen