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JavaScript JavaScript and the DOM (Retiring) Getting a Handle on the DOM Selecting Multiple Elements

Dave Harrison
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Dave Harrison
Front End Web Development Techdegree Student 7,400 Points
Posted by Dave Harrison
.a{fill-rule:evenodd;}techdegree
Dave Harrison
Front End Web Development Techdegree Student 7,400 Points

Selecting Multiple Elements Challenge

I am totally stuck on this code challenge. I have updated the variable listitems with the code below but it doesn't work and I get the following error message ...."There was an error with your code: TypeError: 'undefined' is not an object (evaluating 'listItems[i].style')"

let listItems = document.querySelectorAll("#rainbow"); const colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];

for(var i = 0; i < colors.length; i ++) { listItems[i].style.color = colors[i];
}

index.html 
<!DOCTYPE html>
<html>
  <head>
    <title>Rainbow!</title>
  </head>
  <body>
    <ul id="rainbow">
      <li>This should be red</li>
      <li>This should be orange</li>
      <li>This should be yellow</li>
      <li>This should be green</li>
      <li>This should be blue</li>
      <li>This should be indigo</li>
      <li>This should be violet</li>
    </ul>
    <script src="js/app.js"></script>
  </body>
</html>
js/app.js 
let listItems = document.querySelectorAll("#rainbow");
const colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];

for(var i = 0; i < colors.length; i ++) {
  listItems[i].style.color = colors[i];    
}

2 Answers

clickpass
clickpass
23,992 Points

Adam is right, just change

let listItems = document.querySelectorAll("#rainbow");

to

let listItems = document.querySelectorAll("#rainbow li");
Adam Beer
Adam Beer
11,314 Points
Adam Beer
Adam Beer
11,314 Points

I'm not sure, but try rewrite the querySelectorAll() content on to the li. Probably this is the mistake.