Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

JavaScript JavaScript and the DOM (Retiring) Getting a Handle on the DOM Selecting Multiple Elements

Dave Harrison
seal-mask
.a{fill-rule:evenodd;}techdegree
Dave Harrison
Front End Web Development Techdegree Student 7,400 Points

Selecting Multiple Elements Challenge

I am totally stuck on this code challenge. I have updated the variable listitems with the code below but it doesn't work and I get the following error message ...."There was an error with your code: TypeError: 'undefined' is not an object (evaluating 'listItems[i].style')"

let listItems = document.querySelectorAll("#rainbow"); const colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];

for(var i = 0; i < colors.length; i ++) { listItems[i].style.color = colors[i];
}

index.html
<!DOCTYPE html>
<html>
  <head>
    <title>Rainbow!</title>
  </head>
  <body>
    <ul id="rainbow">
      <li>This should be red</li>
      <li>This should be orange</li>
      <li>This should be yellow</li>
      <li>This should be green</li>
      <li>This should be blue</li>
      <li>This should be indigo</li>
      <li>This should be violet</li>
    </ul>
    <script src="js/app.js"></script>
  </body>
</html>
js/app.js
let listItems = document.querySelectorAll("#rainbow");
const colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];

for(var i = 0; i < colors.length; i ++) {
  listItems[i].style.color = colors[i];    
}

2 Answers

Adam is right, just change

let listItems = document.querySelectorAll("#rainbow");

to

let listItems = document.querySelectorAll("#rainbow li");
Adam Beer
Adam Beer
11,314 Points

I'm not sure, but try rewrite the querySelectorAll() content on to the li. Probably this is the mistake.