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Python Python Collections (2016, retired 2019) Sets Set Math

David Chacón
David Chacón
1,086 Points

Sets by the Beach...part 2

Hey Community!

I feel like I have a question on every challenge! This on I'm just not sure how to take a set as an input. The rest I think is close. Any pointers?

Thanks!

sets.py
COURSES = {
    "Python Basics": {"Python", "functions", "variables",
                      "booleans", "integers", "floats",
                      "arrays", "strings", "exceptions",
                      "conditions", "input", "loops"},
    "Java Basics": {"Java", "strings", "variables",
                    "input", "exceptions", "integers",
                    "booleans", "loops"},
    "PHP Basics": {"PHP", "variables", "conditions",
                   "integers", "floats", "strings",
                   "booleans", "HTML"},
    "Ruby Basics": {"Ruby", "strings", "floats",
                    "integers", "conditions",
                    "functions", "input"}
}

def covers(subject):
    subjectList = []
    for keys, values in COURSES.items():
        if subject.intersection(values):
            subjectList.append(keys)

    return subjectList


def covers_all({item1, item2}):
    subjectsList = []
    set1 = {item1, item2}
    for keys, values in COURSES.items():
        if set1.intersection(values):
            subjectsList.append(keys)

    return subjectsList
David Chacón
David Chacón
1,086 Points

Anything from anyone? Seems like a long time to go without a response at all, especially for a paid service.

Chris Freeman
Chris Freeman
Treehouse Moderator 68,441 Points

Sorry for the slow response. We are all fellow students answering questions. Some questions get missed and fall to later pages. See answer below.

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,441 Points

You are not far off the answer. The function should take a single argument that will be a set.

:point_right: use set1 as the parameter, and remove the assignment to set1 inside the function.

This function is looking for a more precise comparison than a simple intersection. It is looking to see if set1 is a proper subset of `values.

:point_right: use issubset instead of intersection

Post back if you need more help. Good luck!!