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CSS CSS Basics (2014) Basic Layout Styling the "Wildlife" div with Background Properties

setting url

still not getting how to set the url?

style.css
/* Complete the challenge by writing CSS below */
.wildlife {
  background-image: url (../'img/bear.jpg');
}
index.html
<!DOCTYPE html>
<html>
  <head>
    <title>Lake Tahoe</title>
    <link rel="stylesheet" href="page.css">
    <link rel="stylesheet" href="style.css">
  </head>
  <body> 
        <div class="primary-content t-border">
            <p class="intro">
                Lake Tahoe is one of the most breathtaking attractions located in California. It's home to a number of ski resorts, summer outdoor recreation, and tourist attractions. Snow and skiing are a significant part of the area's reputation.
            </p>
            <a class="callout" href="#more">Find out more</a>
      <div class="wildlife">
        <h2>Check out all the Wildlife</h2>
        <p>
          As spawning season approaches, the fish acquire a humpback and protuberant jaw. After spawning, they die and their carcasses provide a feast for gatherings of <a href="#mink">mink</a>, <a href="#bears">bears</a>, and <a href="#eagles">bald eagles</a>.
        </p>
      </div><!-- End .wildlife -->
            <a class="callout" href="#wildlife">See the Wildlife</a>
        </div><!-- End .primary-content -->
  </body>
</html>

1 Answer

Greg Wienecke
Greg Wienecke
20,765 Points
  1. There shouldn't be a space in between url and the paren. So it should look like url(); instead of url ();

  2. In the path ../img/bear.jpg, the two dots tells it to go back one directory, but for this exercise, the img folder is in the same directory so you would use only one dot './img/bear.jpg' or just leave them out entirely 'img/bear.jpg' either way works.

  3. Finally, whether you use the preceding dots and slashes or not, and no matter how many you use, the entire path should be inside the quotes. So if you wanted to go up one directory and look for an img folder, it would be url('../img/bear.jpg'); instead of url (../'img/bear.jpg'); But for this exercise url('img/bear.jpg'); will work.