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Python

Posted by sowmya c
sowmya c
6,966 Points

shopping_list app

shopping_items = []

print("Please enter the items to be added") print("Enter 'DONE' to stop adding the items")

while 1<2: items = input("-")

if items == 'DONE':
    break
shopping_items.append(items)

print("Here is your list:")

for item in items: print(items)

sowmya c
sowmya c
6,966 Points

what is wrong with this code

2 Answers

Thomas Doyle
Thomas Doyle
4,951 Points
Thomas Doyle
Thomas Doyle
4,951 Points 
shopping_items = []


print("Please enter the items to be added") 
print("Enter 'DONE' to stop adding the items")

while True: 

  items = input("-")

  if items.upper() == 'DONE':
    break
  shopping_items.append(items)


print("Here is your list:")

for item in shopping_items: 
  print(item)

For the most part it seemed to be indentation problems to get it working. You also needed to reference your list in your for loop and not items. items was being appended to the shopping list everythim the loop ran and being assigned new information when the loop started again. I'm not sure what the also changed the while 1<2: to while True:

Thomas Doyle
Thomas Doyle
4,951 Points

also added upper() in the if statement so that it does not matter how the user typed 'DONE' it would exit the loop

sowmya c
sowmya c
6,966 Points
sowmya c
sowmya c
6,966 Points

It does not have syntax error.While executing the program is not taking the second input.

Thomas Doyle
Thomas Doyle
4,951 Points

the if statement works fine, it seems the only issue was in your for loop to print the list. it was referencing items which was not where you had stored your list. you had to loop through the shopping_items list.