
Hamed Ali
5,626 PointsSimple question: How to chain the .fail() method to the $.get() method ?
Does someone know how to chain the .fail() method to the $.get() method ? I tried chaining it right at the end, immediately after the .get and also right after the function. None of these worked.
$.get("missing.html", function(data) {
$("#footer").html(data)();
}.fail);
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>AJAX with JavaScript</title>
</head>
<body>
<div id="main">
<h1>AJAX with jQuery</h1>
</div>
<div id="footer"></div>
<script src="jquery.js"></script>
<script src="app.js"></script>
</body>
</html>
1 Answer

Hamed Ali
5,626 PointsWhat you are saying is actually false Steven.
You can chain these (as per challenge requirements) and here is the correct solution:
$.get("missing.html", function(data) { $("#footer").html(data); }).fail(function(jqXHR) { alert(jqXHR.statusText) });
Steven Parker
177,844 PointsSteven Parker
177,844 PointsI forgot to check the challenge itself (I must've been in a hurry!), and was trusting Hamed's description and the jQuery documentation. It says $get() returns a jqXHR object, and .fail() is a method of (and returns) a Deferred object. Further, it says "The Deferred object is chainable, similar to the way a jQuery object is chainable, but it has its own methods."
Check the jQuery documentation for yourself and let me know if I missed something.
But good job finding the solution.