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JavaScript AJAX Basics (retiring) jQuery and AJAX Handle AJAX failures with jQuery

Hamed Ali
Hamed Ali
5,626 Points
Posted by Hamed Ali
Hamed Ali
5,626 Points

Simple question: How to chain the .fail() method to the $.get() method ?

Does someone know how to chain the .fail() method to the $.get() method ? I tried chaining it right at the end, immediately after the .get and also right after the function. None of these worked.

app.js 
$.get("missing.html", function(data) {
  $("#footer").html(data)();
}.fail);
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
</head>
<body>
  <div id="main">
    <h1>AJAX with jQuery</h1>
  </div>
  <div id="footer"></div>
  <script src="jquery.js"></script>
  <script src="app.js"></script>
</body>
</html>

1 Answer

Hamed Ali
Hamed Ali
5,626 Points
Hamed Ali
Hamed Ali
5,626 Points

What you are saying is actually false Steven.

You can chain these (as per challenge requirements) and here is the correct solution:

$.get("missing.html", function(data) { $("#footer").html(data); }).fail(function(jqXHR) { alert(jqXHR.statusText) });

Steven Parker
Steven Parker
231,275 Points
Steven Parker
Steven Parker
231,275 Points

I forgot to check the challenge itself (I must've been in a hurry!), and was trusting Hamed's description and the jQuery documentation. It says $get() returns a jqXHR object, and .fail() is a method of (and returns) a Deferred object. Further, it says "The Deferred object is chainable, similar to the way a jQuery object is chainable, but it has its own methods."

Check the jQuery documentation for yourself and let me know if I missed something.

But good job finding the solution. :+1: