Welcome to the Treehouse Community
The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.
Welser Muñoz4,447 Points
Simple Time Machine
Hi, I have a doubt!, I don't really understand what you are asking me the question.
import datetime starter = datetime.datetime(2015, 10, 21, 16, 29) def delorean(a): now = datetime.datetime.now() diff = starter - now seconds = diff.total_seconds() hours = round(seconds/3600) return hours
Dan Johnson40,532 Points
This challenge is showing the use of timedelta objects. timedeltas let you treat date and times more like basic numeric types. You can add or subtract them to move forward or back in time. For example:
import datetime starter = datetime.datetime(2015, 10, 21, 16, 29) delta = datetime.timedelta(hours=1) one_hour_ahead = starter + delta print(one_hour_ahead)
Will print out:
So to use this in the challenge you'll want to make a function that can take one argument that represents how many hours someone wants to move ahead from the starter date, and return that new date.
import datetime starter = datetime.datetime(2015, 10, 21, 16, 29) def delorean(num): return starter.replace(hour = starter.hour + num)