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###### Enzo Cnop

5,157 Points# Simple way to ask python to check if a number is/is not/ a float.

For the code challenge after creating a number game, I was asked to create a function that would return True if the number entered is even, and False, if the number entered is odd. The code that let me pass the challenge is below.

```
def even_odd(number):
if number % 2 == 0 :
return True
else:
return False
```

My question: Why can't I write this code? (please ignore indentation, i'm not sure how to format code on this website yet.)

```
def even_odd(number):
if number % 2 == float :
return False
else:
return True
```

Surely, python recognizes what a 'float' is, so why can't it check whether or not a number is a float this way? I don't even understand how the code that let me pass the challenge works. Say 5 is the number entered. 6 % 2 = 3, by my understanding of this logic, the code should return false, because the resulting integer is not equal to 0. How does this work. Please help me understand.

## 2 Answers

###### Kurt Maurer

16,725 PointsHey Enzo,

Many languages work solely with integer values unless specified, so 5 / 3 = 1 (1.67, but it returns the integer value). In this case, you could probably get away with it, since Python will actually return a float when performing functions with integers. You could use:

```
isinstance(number, float)
```

But in the case of even/odd, the modulus operator (%) returns the **remainder**, so it is not returning the value like a division operator. The example you cited above, 6 / 3 = 2, but 6 % 3 = 0, since three divides completely into 6. If you did 6 % 5, you would get 1, as there is a remainder of 1 when six is divided by 5. In this challenge, any even number divided by 2 will equal 0; thus, it is even. If it isn't 0, then the number is odd. I hope this helps!

###### Selemawit Gebremedhin

1,331 Pointsnum = int (input ("Enter number: "))

def is_odd (num):

```
if num % 2 != 0:
return True
else:
return False
```

I don't know why it is giving me error