Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community!
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
Amandeep Pasricha
14,932 PointsSo basically, writing const makes the variable name within a function a local variable?
So basically, if a variable inside a function shares the same name as a variable outside the function, you have to specifically classify the variable inside the function so it becomes a local variable?
Why are you allowed to give two variables the same name? I find that peculiar. If the variables were not titled the same, would everything have been fine?
1 Answer

Steven Parker
224,861 PointsThe inner variable is said to "shadow" the outer one. Both exist, but because they have the same name only the inner one is accessible to the inner code. And this is not unique to "const", shadowing occurs just the same with variables declared with "var" or "let".
You are correct that if you use different names then both variables can be accessed from the inner code.