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JavaScript Creating Unchanging Variables With const

Amandeep Pasricha
Amandeep Pasricha
14,932 Points
Posted by Amandeep Pasricha
Amandeep Pasricha
14,932 Points

So basically, writing const makes the variable name within a function a local variable?

So basically, if a variable inside a function shares the same name as a variable outside the function, you have to specifically classify the variable inside the function so it becomes a local variable?

Why are you allowed to give two variables the same name? I find that peculiar. If the variables were not titled the same, would everything have been fine?

1 Answer

Steven Parker
Steven Parker
224,861 Points
Steven Parker
Steven Parker
224,861 Points

The inner variable is said to "shadow" the outer one. Both exist, but because they have the same name only the inner one is accessible to the inner code. And this is not unique to "const", shadowing occurs just the same with variables declared with "var" or "let".

You are correct that if you use different names then both variables can be accessed from the inner code.