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Conor Mosier
925 PointsSo i know there's a better, more efficient, way to do this. Does anyone have any ideas?
continents = [ 'Asia', 'South America', 'North America', 'Africa', 'Europe', 'Antarctica', 'Australia', ]
Your code here
for n in continents:
if n == continents[0]:
print("* " + continents[0])
elif n == continents[3]:
print("* " + continents[3])
elif n == continents[5]:
print("* " + continents[5])
elif n == continents[6]:
print("* " + continents[6])
continents = [
'Asia',
'South America',
'North America',
'Africa',
'Europe',
'Antarctica',
'Australia',
]
# Your code here
for n in continents:
if n == continents[0]:
print("* " + continents[0])
elif n == continents[3]:
print("* " + continents[3])
elif n == continents[5]:
print("* " + continents[5])
elif n == continents[6]:
print("* " + continents[6])
2 Answers
jb30
44,807 PointsYou could treat n as an array and check if n[0] is 'a'.
amandae
15,727 PointsIf I remember correctly, this is supposed to check for words that start with the letter A. Something like this might work. Each word is a string, which is iterable, so we can call it by index. It is something like a list of lists. If you weren't sure about the case, it would be good to use a .upper or .lower method, but these have consistent formatting, so it doesn't matter. This is the same thing jb30 said, just in different words...
for continent in continents:
if continent[0] == A:
print(continent)