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Start your free trialSági János
Courses Plus Student 6,185 PointsSolution
Send me a solution please thanks all
var $link = $.external;
$.external.attr();
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="css/style.css" type="text/css" media="screen" title="no title" charset="utf-8">
<title>Links Page</title>
</head>
<body>
<h1>Links</h1>
<ul>
<li><a href="http://google.com" class="external">Google</a></li>
<li><a href="http://yahoo.com" class="external">Yahoo</a></li>
</ul>
<script src="//code.jquery.com/jquery-1.11.0.min.js" type="text/javascript" charset="utf-8"></script>
<script src="js/app.js" type="text/javascript" charset="utf-8"></script>
</body>
</html>
1 Answer
Steven Parker
231,275 PointsTry breaking the instructions down.
-
Using jQuery only
so we'd start with a selector inside of "$()
" -
all links with the class "external"
links are "a", so the selector would be "a.external
" - add...
the target attribute with the value of "_blank"
.attr("target", "_blank")
So combine those into a single statement and you should have it (no variables needed).
Andres Ramirez
18,094 PointsAndres Ramirez
18,094 PointsWould like to help... But you're not specifying what the solution is needed for!
So may I ask, what are you trying to accomplish with this code?
The first step toward solving a problem, is determining what exactly needs to be solved...