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Nicole Archambault27,852 Points
[SOLVED] Not understanding why "1 && 2 == 1 && 2" evaluates to "false"
I don't know why this just blew my mind... it might have something to do with the fact that it's 5:30 AM and I'm on Treehouse, though.
The video transcript states that
1 && 2 == 1 && 2 evaluates to
false, because it compiles as
1 && (2 == 1) && 2.
How? Why? What? TIA!
EDIT: It was definitely because it's 5:30 AM. From the teacher's notes, I see now that it's actually evaluating it as
1 && false && 2, because it's grouping the logic operators incorrectly (
== has precedence over
&&). If anyone else missed this, hopefully that helps!