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iOS Swift Collections and Control Flow Control Flow With Conditional Statements FizzBuzz Challenge

some kind of stupid mistake living here

Made the changes must be doing something stupid. The code is from his answer video since I couldn't get mine to work, though now I'm running into the same issues...

func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers
    for n in 1...100 {
        if (n % 3 == 0) && (n % 5 == 0) {
            return "FizzBuzz"
        } else if (n % 3 == 0) {
            return "Fizz"
        } else if (n % 5 == 0) {
            return "Buzz"
        } else {
            return n

  // End code
  return "\(n)"

2 Answers

Michael Hulet
Michael Hulet
47,912 Points

Pay attention to what the challenge is asking you to do here. Specifically, the challenge says you don't need a default case where the number doesn't match "Fizz", "Buzz", or "FizzBuzz". Currently this part of your solution produces a compiler error for mismatched types. Also, the challenge also says you don't need to loop over anything at all, because the challenge checker handles that for you. All you have to do is determine if something should match "Fizz", "Buzz", or "FizzBuzz" and return the proper word. Other than that, your code looks fine to me

Thank you sir!