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Python Python Collections (2016, retired 2019) Sets Set Math

Susan krystof
Susan krystof
Courses Plus Student 2,662 Points

Someone please help with this function on sets(python)

Challenge Task 2 of 2 Great work! OK, let's create something a bit more refined. Create a new function named covers_all that takes a single set as an argument. Return the names of all of the courses, in a list, where all of the topics in the supplied set are covered. For example, covers_all({"conditions", "input"}) would return ["Python Basics", "Ruby Basics"]. Java Basics and PHP Basics would be excluded because they don't include both of those topics.

    "Python Basics": {"Python", "functions", "variables",
                      "booleans", "integers", "floats",
                      "arrays", "strings", "exceptions",
                      "conditions", "input", "loops"},
    "Java Basics": {"Java", "strings", "variables",
                    "input", "exceptions", "integers",
                    "booleans", "loops"},
    "PHP Basics": {"PHP", "variables", "conditions",
                   "integers", "floats", "strings",
                   "booleans", "HTML"},
    "Ruby Basics": {"Ruby", "strings", "floats",
                    "integers", "conditions",
                    "functions", "input"}

def covers(corses):
    new_list = []
    for key, value in COURSES.items():
        if value.intersection(corses):
    return new_list      

def covers_all(args):
    for key, value in COURSES.items:
        if args & COURSES[key] ==args:
    return new_list

1 Answer

It seems to me that your function works, except the fact that you forgot to write some symbols: look the code below to see the difference

def covers_all(args): new_list = [] for key, value in COURSES.items(): if args & COURSES[key] ==args: new_list.append(key) return new_list

Also, You can just go with COURSES.keys()