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Python Python Collections (2016, retired 2019) Sets Set Math

Susan krystof
PLUS
Susan krystof
Courses Plus Student 2,662 Points
Posted by Susan krystof
Susan krystof
Courses Plus Student 2,662 Points

Someone please help with this function on sets(python)

Challenge Task 2 of 2 Great work! OK, let's create something a bit more refined. Create a new function named covers_all that takes a single set as an argument. Return the names of all of the courses, in a list, where all of the topics in the supplied set are covered. For example, covers_all({"conditions", "input"}) would return ["Python Basics", "Ruby Basics"]. Java Basics and PHP Basics would be excluded because they don't include both of those topics.

sets.py 
COURSES = {
    "Python Basics": {"Python", "functions", "variables",
                      "booleans", "integers", "floats",
                      "arrays", "strings", "exceptions",
                      "conditions", "input", "loops"},
    "Java Basics": {"Java", "strings", "variables",
                    "input", "exceptions", "integers",
                    "booleans", "loops"},
    "PHP Basics": {"PHP", "variables", "conditions",
                   "integers", "floats", "strings",
                   "booleans", "HTML"},
    "Ruby Basics": {"Ruby", "strings", "floats",
                    "integers", "conditions",
                    "functions", "input"}
}    

def covers(corses):
    new_list = []
    for key, value in COURSES.items():
        if value.intersection(corses):
            new_list.append(key)
    return new_list      


def covers_all(args):
    new_list[]
    for key, value in COURSES.items:
        if args & COURSES[key] ==args:
            new_list.append(key)
    return new_list

1 Answer

Unsubscribed User
Unsubscribed User
3,284 Points
Unsubscribed User
Unsubscribed User
3,284 Points

It seems to me that your function works, except the fact that you forgot to write some symbols: look the code below to see the difference

def covers_all(args): new_list = [] for key, value in COURSES.items(): if args & COURSES[key] ==args: new_list.append(key) return new_list

Unsubscribed User
Unsubscribed User
3,284 Points

Also, You can just go with COURSES.keys()