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JavaScript Node.js Basics (2014) Building a Command Line Application Using try and catch

Posted by himsa devil
himsa devil
Courses Plus Student 297 Points

Something bad is going to happen. Use a try block in the appropriate place to catch an error. Include a catch block with

help

app.js 
var jsonString = 'This is not a JSON String';
var jsonObject = JSON.parse(jsonString);

try { //var jsonString = 'This is not a JSON String'; 
     //var jsonObject = JSON.parse(jsonString); 
    } 
catch(error) {}

1 Answer

Walter Allen
seal-mask
.a{fill-rule:evenodd;}techdegree
Walter Allen
iOS Development with Swift Techdegree Student 16,023 Points
Walter Allen
.a{fill-rule:evenodd;}techdegree
Walter Allen
iOS Development with Swift Techdegree Student 16,023 Points

Hey, HImsa... What the question wants you to do is to put a try/catch block AROUND the existing code, not after it. Does that help? If not, let me know and I can get more specific. :)