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Andrew Wiley
27,097 Pointssomething is wrong when using pointers
When I put in the code for pointers I get back "N is always the same as N". If c is pointing to k then why is it giving me N?
{
char *letter;
char c = "k";
letter = &c;
printf("%c is always the same as %c\n", c, *letter);
return 0;
}
1 Answer
Richard Lu
20,185 PointsHey Andrew,
The problem that I see is that you're assigning a string to a char variable. Try this instead:
char *letter;
char c = 'k'; // use single quotes
letter = &c;
printf("%c is always the same as %c\n", c, *letter);
return 0;
Andrew Wiley
27,097 PointsAndrew Wiley
27,097 Pointsmain.c:16:10: Incompatible pointer to integer conversion initializing 'char' with an expression of type 'char [2]'