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JavaScript JavaScript Foundations Arrays Methods: Part 2

sort using length

I'm working on the challenge that requires I use "sort"with length inside. I feel like I'm very close, but can't get a correct answer. Can anyone correct my code?


<!DOCTYPE html>
<html lang="en">
    <title> JavaScript Foundations: Arrays</title>
      html {
        background: #FAFAFA;
        font-family: sans-serif;
    <h1>JavaScript Foundations</h1>
    <h2>Arrays: Methods Part 1</h2>
      var saying1 = ["The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog"];
      var saying2 = ["The", "quick", "brown", "fox", "jumped", "over", "the", "lazy", "dog's", "back"];
      saying2.sort(function (a, b)
                     return a-b;

1 Answer

You are indeed pretty close, you are just not getting the length for the correct strings.

      var saying1 = ["The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog"];
      var saying2 = ["The", "quick", "brown", "fox", "jumped", "over", "the", "lazy", "dog's", "back"];
      saying2.sort(function(a, b){

        // Get the lengths of the strings that will be compared by the sort() method and subtract then from one another.
        // The result is sent to the sort method, which will do some magic and arrays will be organized.
        return a.length - b.length;

If you don't like magic, you can uncover the truth of sort() here.

Erik Thank you sooo much. I fought with that for longer than I care to share!