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Python Python Basics (2015) Python Data Types Use .split() and .join()

Posted by ak37
ak37
2,344 Points

Split and Join Excercise

I need help with this exercise. I am stumped as to what the mistake is

banana.py 
available = "banana split;hot fudge;cherry;malted;black and white"
sundaes = available.split(';')
menu = "Our available flavors are: {}."
display_menu = sundaes.join(", ")
menu = menu.format(display_menu)

2 Answers

Josh Keenan
Josh Keenan
19,652 Points
Josh Keenan
Josh Keenan
19,652 Points 
available = "banana split;hot fudge;cherry;malted;black and white"
sundaes = available.split(";")
menu = "Our available flavors are: {}.".format(", ".join(sundaes))
display_menu = (", ").join(menu)

Here's my solution, a lot of people get stuck on this so don't worry, you have to call .join() on a string and give it the thing you want to manipulate as a parameter, so this is how you do it!

Igor Ević
Igor Ević
5,827 Points 
display_menu = (", ").join(menu)

is wrong. You don't need display_menu variable because you have value for menu variable in one row. But if you use display_menu, then you have:

available = "banana split;hot fudge;cherry;malted;black and white"
sundaes = available.split(";")
display_menu = (", ").join(sundaes)
menu = "Our available flavors are: {}.".format(display_menu)
Josh Keenan
Josh Keenan
19,652 Points
Josh Keenan
Josh Keenan
19,652 Points

You can do it in one line yes, but when someone is learning it is better that they see it more clearly and understand everything first, before going to the best solutions. Also my code passes fine it doesn't have to be as you have it

Igor Ević
Igor Ević
5,827 Points
Igor Ević
Igor Ević
5,827 Points

Your code passes fine because only menu variable is checked. What's value of your display_menu variable?

Josh Keenan
Josh Keenan
19,652 Points
Josh Keenan
Josh Keenan
19,652 Points

oh yeah my bad I didn't realise I did it in one line xD, did it automatically and then did the other bit for the asker