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Python Python Basics Functions and Looping Create a Function

Tyler Cortez
Tyler Cortez
2,771 Points
Posted by Tyler Cortez
Tyler Cortez
2,771 Points

square

trouble getting the math to square rather than multiplying the numbers together if I do number * 3 it just goes 333

squaring.py 
def square(number):
    return number * 3
result = square('3')
print(result)

1 Answer

Bramyn Payne
seal-mask
.a{fill-rule:evenodd;}techdegree
Bramyn Payne
Full Stack JavaScript Techdegree Student 19,560 Points
Bramyn Payne
.a{fill-rule:evenodd;}techdegree
Bramyn Payne
Full Stack JavaScript Techdegree Student 19,560 Points

Hey Tyler,

I think your problem is that you pass '3' into square(). This treats it as a string, so it repeats the string three times. Instead, you should use square(3) so that it treats it as an integer.

Also, the function should return the square of number. Even though the number = 3 in this case, the function should still use number * number.

I hope this helps, and good luck!