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# square of a number

This challenge is similar to an earlier one. Remember, though, I want you to practice! You'll probably want to use try and except on this one. You might have to not use the else block, though.

Write a function named squared that takes a single argument.

If the argument can be converted into an integer, convert it and return the square of the number (num ** 2 or num * num).

If the argument cannot be turned into an integer (maybe it's a string of non-numbers?), return the argument multiplied by its length. Look in the file for examples.

Thank you

squared.py
```# EXAMPLES
# squared(5) would return 25
def squared(num):
try:
int(num)
except valueError:
print("thats not a number")
else:
print(num**2)
#    if num = int(number):
#        return(num**2)
#    else:
#        print(num**2)
# squared("2") would return 4
# squared("tim") would return "timtimtim"
```

PLUS
```# Write a function named squared that takes a single argument.
def squared(num): # done, good.

# If the argument can be converted into an integer, convert it and
# return the square of the number (num ** 2 or num * num).
try:

# it's good you're testing it here, but why not just return here too?
# perhaps try returning (int)num ** 2 directly here
int(num)

# we don't care at this point why type of exception is thrown, just that it is. But either way :)
except ValueError:

# if it failed casting it means we're here and it's not a number
# so let's just return num * len(num) at this point, then we don't need an else
print("thats not a number") #return here instead of print

# an else isn't necessary anymore because the requirements are met and
# all scenarions are dealt with already :)
else:
print(num**2)
```

Thought I'd just put the reasoning in comments.
You're almost there, keep going

Hope that helps
Dave