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# Squared function

It says "Bummer! 'squared' didn't return the correct result"

What's wrong???

squared.py
```# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"

def squared(arg):
try:
if int(arg) == arg:
return arg ** 2
except:
try:
return int(arg) ** 2
except:
return arg * len(arg)
```

STAFF

Ok you're checking in your code to see if the int version of the argument is equal to the argument. If it is, return the square of it. Then if it isn't possible to make it an int... you check it again to see if it can be made an int and returned as a square directly. When that fails then you send back the string printed out a certain number of times. But you don't say what kind of exception you're looking to "catch".

Somewhere in all that you managed to overthink it a bit, I think. Here's the code I used. I hope it helps!

```def squared(arg):
try:
return int(arg) ** 2
except ValueError:
return arg * len(arg)
```

Thanks you so mush! :D