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# squared. what's wrong in here?

def squared(value): try: (value, int) == True: return int(value) ** 2 except ValueError:
return value * len(value)

squared.py
```# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(value):
try:
(value, int) == True:
return int(value) ** 2
except ValueError:
return value * len(value)
```

hello, there are some syntax errors that may be causing your problem.

```def squared(value):
try:
(value, int) == True      # remove : here
return int(value) ** 2    # no indentation here
except ValueError:
return value * len(value)
```

Jeremiah is partly correct, but the line after "try" serves no purpose even after syntax correction.

```def squared(value):
try:
#       (value, int) == True:     - remove this line entirely
return int(value) ** 2    # fix the indentation here
except ValueError:
return value * len(value)
```