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Peter Falcone
Courses Plus Student 1,108 Pointssquared.py
I've tried numerous things. I feel the problem is likely the line just below 'try:' where I have changed out several different things.
# EXAMPLES
# squared(5) would return 25
# squared("2") would return 4
# squared("tim") would return "timtimtim"
def squared(num):
try:
int(num)
return(num * num)
except ValueError:
return(num * len(num))
2 Answers

Ryan S
27,276 PointsHi Peter,
You are really close, but the issue is that calling int(num)
on its own doesn't permanently convert the number to an integer. You need to assign it back to "num" so that the variable gets updated and can be successfully multiplied in your return statement.
def squared(num):
try:
num = int(num)
return(num * num)
except ValueError:
return(num * len(num))