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Peter FalconeCourses Plus Student 1,108 Points
I've tried numerous things. I feel the problem is likely the line just below 'try:' where I have changed out several different things.
# EXAMPLES # squared(5) would return 25 # squared("2") would return 4 # squared("tim") would return "timtimtim" def squared(num): try: int(num) return(num * num) except ValueError: return(num * len(num))
Ryan S27,276 Points
You are really close, but the issue is that calling
int(num) on its own doesn't permanently convert the number to an integer. You need to assign it back to "num" so that the variable gets updated and can be successfully multiplied in your return statement.
def squared(num): try: num = int(num) return(num * num) except ValueError: return(num * len(num))