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Daniel Glennie42,854 Points
Squaring function won't return correct answer
I have tried various minor adjustments to this code, using ValueError and TypeError in the except block and defining a ret variable to pass the return values to. I've tried using the isinstance method to check if num is of type int and also the type(int) method but I don't seem to be getting anywhere. I know it'll be something simple that I'm missing. Any ideas?
# EXAMPLES # squared(5) would return 25 # squared("2") would return 4 # squared("tim") would return "timtimtim" def squared(num): try: if type(num) is int: return num * num except TypeError: return num * len(num)
Russell SawyerFront End Web Development Techdegree Student 15,705 Points
You are pretty close. You just need to make a couple changes.
def squared(arg): try: arg = int(arg) #< this line determines if the variable is a number or integer except ValueError: return arg * len(arg) else: return arg ** 2
Why doesn't this work?
def squared(num): try: return int(num) * int(num) #<-- Doesn't this check to see if "num" is a integer too? except ValueError: print(len(num) * num)