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# Squaring.py Challenge

How do I call a new function and pass it a new variable? I am on part two of the challenge and I created a function that squares a number entered.

squaring.py
```def square(number):
return(number * number)
```

To call a function with an argument, just put the argument between the parens. e.x.:

```def square(number):
return number * number

# The below line calls the function "square", but it doesn't do anything with
# the returned value:
square(3)
```

If you merely call `square`, however, it will only return the value `3`. What happens to `3`? Well, it isn't being used, or stored within a variable, so it's kind of just floating in space. To assign it to a variable, you could write this:

```result = square(3)
```

I hope this helps! yes it does thank you so much!

If it helped, remember to provide a "Best Answer" on the next step it is asking to store the value from the function call but im not sure how to do that i tried this but its not working import math

def square(number): return (number * number)

```result = square(number)
```

square(3)